Comments for Math 267 http://blogs.ubc.ca/mat267 Mathematical Methods for EECE Mon, 15 Apr 2013 06:35:18 +0000 hourly 1 http://wordpress.org/?v=3.5.1 Comment on Homework #10 by Ian Zwiers http://blogs.ubc.ca/mat267/exercises/homework-10/#comment-113 Ian Zwiers Mon, 15 Apr 2013 06:35:18 +0000 http://blogs.ubc.ca/mat267/?page_id=748#comment-113 No, the roots are unique.

(z – 1 – sqrt(i)) * (z – 1 + sqrt(i)) = (z^2 -2 z +2)

]]> Comment on Homework #10 by Himanshu http://blogs.ubc.ca/mat267/exercises/homework-10/#comment-110 Himanshu Sun, 14 Apr 2013 22:21:33 +0000 http://blogs.ubc.ca/mat267/?page_id=748#comment-110 For Q5b
The roots for (z^2 – 2 Z +1 – i) could be (1 +/- sqrt(i)) as well, right?
because (z – 1 – sqrt(i)) * (z – 1 + sqrt(i)) = (z^2 – 2 Z +1 – i)

]]> Comment on Homework #10 by Ian Zwiers http://blogs.ubc.ca/mat267/exercises/homework-10/#comment-106 Ian Zwiers Sun, 14 Apr 2013 05:50:47 +0000 http://blogs.ubc.ca/mat267/?page_id=748#comment-106 I don’t know of any shortcuts for this one.

]]> Comment on Homework #10 by Ian Zwiers http://blogs.ubc.ca/mat267/exercises/homework-10/#comment-105 Ian Zwiers Sun, 14 Apr 2013 05:47:45 +0000 http://blogs.ubc.ca/mat267/?page_id=748#comment-105 If z_1 and z_2 are solutions of a quadratic polynomial z^2 + z + 1-i, then that means:
z^2 + z + 1-i = (z-z_1)(z-z_2)

]]> Comment on Homework #10 by Ian Zwiers http://blogs.ubc.ca/mat267/exercises/homework-10/#comment-104 Ian Zwiers Sun, 14 Apr 2013 05:46:34 +0000 http://blogs.ubc.ca/mat267/?page_id=748#comment-104 Haha. Yes. Another fix. Thanks!

]]> Comment on Final Exam Details by Ian Zwiers http://blogs.ubc.ca/mat267/final-exam-details/#comment-103 Ian Zwiers Sun, 14 Apr 2013 05:43:08 +0000 http://blogs.ubc.ca/mat267/?p=752#comment-103 If you don’t calculate an integral, you are guaranteed to lose marks. If you don’t calculate a derivative, you might. It will depend on the marking scheme. To be safe, you should, but its up to your exam-time management.

]]> Comment on Homework #10 by Ian Zwiers http://blogs.ubc.ca/mat267/exercises/homework-10/#comment-102 Ian Zwiers Sun, 14 Apr 2013 05:30:29 +0000 http://blogs.ubc.ca/mat267/?page_id=748#comment-102 Yes, a square root was missing. I’ve updated the solutions. Thank you!

]]> Comment on Homework #10 by C http://blogs.ubc.ca/mat267/exercises/homework-10/#comment-101 C Sun, 14 Apr 2013 05:29:06 +0000 http://blogs.ubc.ca/mat267/?page_id=748#comment-101 For 2 b is there a short way to find a, b, and c in the PFE? Multiplying out all the terms is really a big mess, and the residue method doesn’t seem to work because of the ‘z’s in the numerator. Thanks.

]]> Comment on Homework #10 by alex http://blogs.ubc.ca/mat267/exercises/homework-10/#comment-100 alex Sun, 14 Apr 2013 03:05:47 +0000 http://blogs.ubc.ca/mat267/?page_id=748#comment-100 Is the answer to 5a missing a ‘z’ in the numerator? What happened to the ‘z’ that was being multiplied by x(z)?

]]> Comment on Final Exam Details by Daniel Chong http://blogs.ubc.ca/mat267/final-exam-details/#comment-97 Daniel Chong Sun, 14 Apr 2013 01:29:41 +0000 http://blogs.ubc.ca/mat267/?p=752#comment-97 On homework, we would lose marks if we did not calculate derivatives i\frac{d}{dw}. However, on MT2, no marks were lost for leaving the answer in the form i\frac{d}{dw} without taking the derivative of the Fourier Transform. Is this going to be true for the final too? As it would save much time not having to calculate these derivatives sometimes (and leave less room for error).

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