{"id":149,"date":"2017-02-04T22:31:11","date_gmt":"2017-02-05T05:31:11","guid":{"rendered":"https:\/\/blogs.ubc.ca\/mrpletsch\/?p=149"},"modified":"2019-09-03T10:54:17","modified_gmt":"2019-09-03T17:54:17","slug":"2-7-dna-replication-transcription-translation","status":"publish","type":"post","link":"https:\/\/blogs.ubc.ca\/mrpletsch\/2017\/02\/04\/2-7-dna-replication-transcription-translation\/","title":{"rendered":"2.7 DNA Replication, Transcription, Translation"},"content":{"rendered":"<p><strong>Essential Idea:<\/strong> Genetic information in DNA can be accurately copied and can be translated to make the proteins needed by the cell.<\/p>\n<p><a href=\"https:\/\/www.youtube.com\/watch?v=8kK2zwjRV0M&amp;t=24s\">DNA structure and replication crash course<\/a><\/p>\n\n<p><a href=\"https:\/\/www.youtube.com\/watch?v=itsb2SqR-R0\">Transcription and Translation crash course<\/a><\/p>\n<p><a href=\"http:\/\/www.shamnair.com\/immunology\/teaching-science\/lectures\/biol115_2014_lecture-7_tran.pdf\">Protein Synthesis slides (Bio 115)<\/a><\/p>\n\n<h3><strong>DNA Replication &#8211; Basics<br \/>\n<\/strong><\/h3>\n<p><strong>2.7.U1 -The replication of DNA is semi-conservative and depends on complementary base pairing.<\/strong><\/p>\n<figure id=\"attachment_141\" aria-describedby=\"caption-attachment-141\" style=\"width: 280px\" class=\"wp-caption alignright\"><img loading=\"lazy\" decoding=\"async\" class=\"size-medium wp-image-141\" src=\"https:\/\/blogs.ubc.ca\/mrpletsch\/files\/2017\/02\/dnastruc2-280x300.png\" alt=\"\" width=\"280\" height=\"300\" srcset=\"https:\/\/blogs.ubc.ca\/mrpletsch\/files\/2017\/02\/dnastruc2-280x300.png 280w, https:\/\/blogs.ubc.ca\/mrpletsch\/files\/2017\/02\/dnastruc2.png 532w\" sizes=\"auto, (max-width: 280px) 100vw, 280px\" \/><figcaption id=\"caption-attachment-141\" class=\"wp-caption-text\">Figure 1: DNA complementary base pairing<\/figcaption><\/figure>\n<p>Two DNA strands are held together by hydrogen bonding between <u>complementary base pairs.<\/u><\/p>\n<ul>\n<li>Adenine is always matched with Thymine with two hydrogen bonds<\/li>\n<li>Guanine is always matched with Cytosine with three hydrogen bond<\/li>\n<li>This is due to the molecular structure of the base pairs.<\/li>\n<li>Base paring ensures two identical DNA strands are formed after replication is complete<\/li>\n<li>The parental strand acts as a template and therefore each replicated strand is identical and each daughter cell has the same DNA.<\/li>\n<\/ul>\n<figure id=\"attachment_150\" aria-describedby=\"caption-attachment-150\" style=\"width: 408px\" class=\"wp-caption aligncenter\"><img loading=\"lazy\" decoding=\"async\" class=\" wp-image-150\" src=\"https:\/\/blogs.ubc.ca\/mrpletsch\/files\/2017\/02\/2.71-300x128.png\" alt=\"\" width=\"408\" height=\"182\" \/><figcaption id=\"caption-attachment-150\" class=\"wp-caption-text\">Figure 2: DNA replication outline<\/figcaption><\/figure>\n<p>Due to this, DNA replication is <strong>semi-conservative<\/strong> \u2013 or each new DNA strand has <strong>one parental strand (template) and one newly synthesized strand.<\/strong><\/p>\n<figure id=\"attachment_151\" aria-describedby=\"caption-attachment-151\" style=\"width: 387px\" class=\"wp-caption aligncenter\"><img loading=\"lazy\" decoding=\"async\" class=\" wp-image-151\" src=\"https:\/\/blogs.ubc.ca\/mrpletsch\/files\/2017\/02\/2.72-300x182.png\" alt=\"\" width=\"387\" height=\"235\" srcset=\"https:\/\/blogs.ubc.ca\/mrpletsch\/files\/2017\/02\/2.72-300x182.png 300w, https:\/\/blogs.ubc.ca\/mrpletsch\/files\/2017\/02\/2.72-768x466.png 768w, https:\/\/blogs.ubc.ca\/mrpletsch\/files\/2017\/02\/2.72-552x335.png 552w, https:\/\/blogs.ubc.ca\/mrpletsch\/files\/2017\/02\/2.72.png 975w\" sizes=\"auto, (max-width: 387px) 100vw, 387px\" \/><figcaption id=\"caption-attachment-151\" class=\"wp-caption-text\">Figure 3: Semi-conservative DNA replication<\/figcaption><\/figure>\n<p>How do we know DNA replication is <b>semi-conservative?<\/b><\/p>\n<ul>\n<li><u>Originally, there were three proposed methods:<\/u><\/li>\n<li>1) <b>Conservative<\/b> \u2013 parental strand rejoins after replication<\/li>\n<li>2) <b>Dispersive<\/b> \u2013 parental DNA double helix is broken into segments that act as templates<\/li>\n<li>3) <b>Semi<\/b><b>-conservative <\/b>&#8211; two parental DNA strands separate and each of those strands then serves as a template for the synthesis of a new DNA strand.<\/li>\n<\/ul>\n<figure id=\"attachment_152\" aria-describedby=\"caption-attachment-152\" style=\"width: 300px\" class=\"wp-caption aligncenter\"><img loading=\"lazy\" decoding=\"async\" class=\"size-medium wp-image-152\" src=\"https:\/\/blogs.ubc.ca\/mrpletsch\/files\/2017\/02\/2.75-300x212.png\" alt=\"\" width=\"300\" height=\"212\" srcset=\"https:\/\/blogs.ubc.ca\/mrpletsch\/files\/2017\/02\/2.75-300x212.png 300w, https:\/\/blogs.ubc.ca\/mrpletsch\/files\/2017\/02\/2.75-768x542.png 768w, https:\/\/blogs.ubc.ca\/mrpletsch\/files\/2017\/02\/2.75-1024x723.png 1024w, https:\/\/blogs.ubc.ca\/mrpletsch\/files\/2017\/02\/2.75-1140x805.png 1140w, https:\/\/blogs.ubc.ca\/mrpletsch\/files\/2017\/02\/2.75-552x390.png 552w, https:\/\/blogs.ubc.ca\/mrpletsch\/files\/2017\/02\/2.75.png 1324w\" sizes=\"auto, (max-width: 300px) 100vw, 300px\" \/><figcaption id=\"caption-attachment-152\" class=\"wp-caption-text\">Figure 5: The three proposed methods of DNA replication<\/figcaption><\/figure>\n<p>In 1957, Meselson and Stahl conducted an experiment providing evidence for <strong>semi-conservative replication.<\/strong><\/p>\n<p><strong>2.7.A2 &#8211; Analysis of Meselson and Stahl\u2019s results to obtain support for the theory of semi-conservative replication of DNA.<\/strong><\/p>\n<h5>Meselson and Stahl experiment:<\/h5>\n<div class=\"paragraph\" data-perseus-paragraph-index=\"2\" data-reactid=\".11dueca0wsg.1.0.4.0.$4.$4.$2\">\n<div class=\"paragraph\" data-reactid=\".11dueca0wsg.1.0.4.0.$4.$4.$2.$2\"><em>&#8220;They began by growing E. coli in medium, or nutrient broth, containing a &#8220;heavy&#8221; isotope of nitrogen, <span class=\"katex\"><span class=\"katex-mathml\">15N<\/span><\/span>. (An <strong data-reactid=\".11dueca0wsg.1.0.4.0.$4.$4.$2.$2.$11\">isotope<\/strong> is just a version of an element that differs from other versions by the number of neutrons in its nucleus.) When grown on medium containing heavy <span class=\"katex\"><span class=\"katex-mathml\">15N<\/span><\/span>, the bacteria took up the nitrogen and used it to synthesize new biological molecules, including DNA.<\/em><\/div>\n<\/div>\n<div class=\"paragraph\" data-perseus-paragraph-index=\"3\" data-reactid=\".11dueca0wsg.1.0.4.0.$4.$4.$3\">\n<div class=\"paragraph\" data-reactid=\".11dueca0wsg.1.0.4.0.$4.$4.$3.$3\"><em>After many generations growing in the <span class=\"katex\"><span class=\"katex-mathml\">15N<\/span><\/span> medium, the nitrogenous bases of the bacteria&#8217;s DNA were all labeled with heavy <span class=\"katex\"><span class=\"katex-mathml\">15N<\/span><\/span>. Then, the bacteria were switched to medium containing a &#8220;light&#8221; <span class=\"katex\"><span class=\"katex-mathml\">14N<\/span><\/span> isotope and allowed to grow for several generations. DNA made after the switch would have to be made up of <span class=\"katex\"><span class=\"katex-mathml\">14N<\/span><\/span>, as this would have been the only nitrogen available for DNA synthesis.<\/em><\/div>\n<\/div>\n<div class=\"paragraph\" data-perseus-paragraph-index=\"4\" data-reactid=\".11dueca0wsg.1.0.4.0.$4.$4.$4\">\n<div class=\"paragraph\" data-reactid=\".11dueca0wsg.1.0.4.0.$4.$4.$4.$4\"><em>Meselson and Stahl knew how often E. coli cells divided, so they were able to collect small samples in each generation and extract and purify the DNA. They then measured the density of the DNA (and, indirectly, its <span class=\"katex\"><span class=\"katex-mathml\">15N <\/span><\/span>and <span class=\"katex\"><span class=\"katex-mathml\">14N<\/span><\/span> content) using <strong data-reactid=\".11dueca0wsg.1.0.4.0.$4.$4.$4.$4.$13\">density gradient centrifugation<\/strong>.<\/em><\/div>\n<\/div>\n<div class=\"paragraph\" data-perseus-paragraph-index=\"5\" data-reactid=\".11dueca0wsg.1.0.4.0.$4.$4.$5\">\n<div class=\"paragraph\" data-reactid=\".11dueca0wsg.1.0.4.0.$4.$4.$5.$5\"><em>This method separates molecules such as DNA into bands by spinning them at high speeds in the presence of another molecule, such as cesium chloride, that forms a density gradient from the top to the bottom of the spinning tube. Density gradient centrifugation allows very small differences\u2014like those between <span class=\"katex\"><span class=\"katex-mathml\">15N<\/span><\/span> and <span class=\"katex\"><span class=\"katex-mathml\">14N<\/span><\/span>, N-labeled DNA\u2014to be detected.&#8221;<\/em><\/div>\n<div class=\"paragraph\" data-reactid=\".11dueca0wsg.1.0.4.0.$4.$4.$5.$5\"><\/div>\n<div class=\"paragraph\" data-reactid=\".11dueca0wsg.1.0.4.0.$4.$4.$5.$5\"><\/div>\n<div class=\"paragraph\" data-reactid=\".11dueca0wsg.1.0.4.0.$4.$4.$5.$5\"><em>Quoted from https:\/\/www.khanacademy.org\/science\/biology\/dna-as-the-genetic-material\/dna-replication\/a\/mode-of-dna-replication-meselson-stahl-experiment<\/em><\/div>\n<div class=\"paragraph\" data-reactid=\".11dueca0wsg.1.0.4.0.$4.$4.$5.$5\"><\/div>\n<\/div>\n<div class=\"paragraph\" data-reactid=\".11dueca0wsg.1.0.4.0.$4.$4.$5.$5\"><\/div>\n<div class=\"paragraph\" data-reactid=\".11dueca0wsg.1.0.4.0.$4.$4.$5.$5\">So,<\/div>\n<div class=\"paragraph\" data-reactid=\".11dueca0wsg.1.0.4.0.$4.$4.$5.$5\">\n<ul>\n<li>DNA is semi-conservative in terms of replication.<\/li>\n<li>Using the parental DNA strand as a template, two identical strands of DNA are produced.<\/li>\n<li>But, in order for base pairing to occur, we need to unzip to DNA.<\/li>\n<\/ul>\n<p>&nbsp;<\/p>\n<\/div>\n<p><iframe loading=\"lazy\" width=\"700\" height=\"394\" src=\"https:\/\/www.youtube.com\/embed\/TNKWgcFPHqw?feature=oembed\" frameborder=\"0\" allowfullscreen><\/iframe><\/p>\n<h3><strong>DNA <\/strong><strong>Replication<\/strong><\/h3>\n<p><em>DNA molecule is split down the middle and forms two, identical copies<\/em><\/p>\n<h5><strong>2.7.U2 &#8211; Helicase unwinds the double helix and separates the two strands by breaking hydrogen bonds.<\/strong><\/h5>\n<p>Steps of Transcription:<\/p>\n<p>1. <span style=\"text-decoration: underline;\"><strong>Initiation<\/strong><\/span><\/p>\n<ul>\n<li><u><b>DNA Helicase <\/b><\/u>(an unzipping enzyme) moves along DNA molecule breaking hydrogen bonds between complementary base pairs.<\/li>\n<li><b>Replication bubble <\/b>\u2013 Unwound\/open region of a DNA helix where replication occurs.<\/li>\n<li>Separated DNA strands form a <b>replication bubble at the origin of <\/b><b>replication<\/b><\/li>\n<li style=\"text-align: left;\">Initiator protein binds to an origin of replication and triggers unzipping (several ori\n<figure id=\"attachment_153\" aria-describedby=\"caption-attachment-153\" style=\"width: 300px\" class=\"wp-caption alignright\"><img loading=\"lazy\" decoding=\"async\" class=\"size-medium wp-image-153\" src=\"https:\/\/blogs.ubc.ca\/mrpletsch\/files\/2017\/02\/2.76-300x189.png\" alt=\"\" width=\"300\" height=\"189\" srcset=\"https:\/\/blogs.ubc.ca\/mrpletsch\/files\/2017\/02\/2.76-300x189.png 300w, https:\/\/blogs.ubc.ca\/mrpletsch\/files\/2017\/02\/2.76-552x348.png 552w, https:\/\/blogs.ubc.ca\/mrpletsch\/files\/2017\/02\/2.76.png 732w\" sizes=\"auto, (max-width: 300px) 100vw, 300px\" \/><figcaption id=\"caption-attachment-153\" class=\"wp-caption-text\">Figure 6: DNA replication bubble<\/figcaption><\/figure>\n<p>gins of replication)<\/li>\n<li>As helicase unzips the DNA, strain on the helix increases.<\/li>\n<li>Must relieves tension periodically.<\/li>\n<li><b>Topoisomerase<\/b> \u2013 Enzyme that cuts DNA and reseals it with fewer twists (relieves tension).<\/li>\n<li>We now have two template (parental) strands with bases exposed. Complementary base paring can occur.<\/li>\n<\/ul>\n<p><strong>2.7.U3 &#8211; DNA polymerase links nucleotides together to form a new strand, using the pre-existing strand as a template.<\/strong><\/p>\n<p>2. <span style=\"text-decoration: underline;\"><strong>Elongation<\/strong><\/span><\/p>\n<ul>\n<li>Free-floating nucleotides form complementary base pairs with the expo\n<figure id=\"attachment_157\" aria-describedby=\"caption-attachment-157\" style=\"width: 300px\" class=\"wp-caption alignright\"><img loading=\"lazy\" decoding=\"async\" class=\"size-medium wp-image-157\" src=\"https:\/\/blogs.ubc.ca\/mrpletsch\/files\/2017\/02\/2.77-300x150.png\" alt=\"\" width=\"300\" height=\"150\" srcset=\"https:\/\/blogs.ubc.ca\/mrpletsch\/files\/2017\/02\/2.77-300x150.png 300w, https:\/\/blogs.ubc.ca\/mrpletsch\/files\/2017\/02\/2.77-768x384.png 768w, https:\/\/blogs.ubc.ca\/mrpletsch\/files\/2017\/02\/2.77-552x276.png 552w, https:\/\/blogs.ubc.ca\/mrpletsch\/files\/2017\/02\/2.77.png 835w\" sizes=\"auto, (max-width: 300px) 100vw, 300px\" \/><figcaption id=\"caption-attachment-157\" class=\"wp-caption-text\">Figure 7: DNA replication enzymes<\/figcaption><\/figure>\n<p>sed bases of the unzipped parental strand.<\/li>\n<li><b>DNA Polymerase<\/b> (enzyme) helps <u><b>covalently<\/b><\/u> bond the new paired bases together (sugars and phosphate groups of nucleotides)<\/li>\n<li>DNA Polymerase <u><b>always <\/b><\/u>works in a <u><b>5\u2019 to 3\u2019 <\/b><\/u><u><b>direction<\/b><\/u><\/li>\n<\/ul>\n<p><b>Question: <\/b><i>If DNA polymerase always works in a 5\u2019 to 3\u2019 direction, what does these mean for the newly synthesized strands<\/i><i>?<\/i><\/p>\n<p>Each strand is synthesized in opposite directions of each other &#8211; One will run <strong>continuousl<\/strong>y -&gt; moves in the same direction as helicase unzips. The other will have to be synthesized <strong>discontinuously -&gt; <\/strong>moves in the opposite direction as helicase unzips. To elaborate:<\/p>\n<figure id=\"attachment_175\" aria-describedby=\"caption-attachment-175\" style=\"width: 350px\" class=\"wp-caption aligncenter\"><img loading=\"lazy\" decoding=\"async\" class=\" wp-image-175\" src=\"https:\/\/blogs.ubc.ca\/mrpletsch\/files\/2017\/02\/Screen-Shot-2017-02-06-at-11.00.19-AM-300x186.png\" alt=\"\" width=\"350\" height=\"220\" \/><figcaption id=\"caption-attachment-175\" class=\"wp-caption-text\">Figure 8: DNA replication (showing replication fork)<\/figcaption><\/figure>\n<p><u><b>Leading strand<\/b><\/u> &#8211; 3\u2019 to 5\u2019<\/p>\n<ul>\n<li>Nucleotides can readily be added to the newly synthesized strand in the opposite 5\u2019 to 3\u2019 direction.<\/li>\n<li><b>Continuous synthesis<\/b> (it occurs in the direction of DNA being unzipped i.e. replication fork)<\/li>\n<\/ul>\n<p><u><b>Lagging strand <\/b><\/u><b>\u2013 <\/b>5\u2019 to 3\u2019<\/p>\n<ul>\n<li>The nucleotides are added in the <b>opposite direction of the DNA unzip (i.e. away from the replication fork)<\/b><\/li>\n<li><b>Discontinuous synthesis<\/b> (It is \u201clagging\u201d behind)<\/li>\n<\/ul>\n<p><b>Question: <\/b><i>If the enzyme moves away from the fork, and the fork is uncovering new DNA that needs to be replicated, then how can the lagging strand be replicated at all?<\/i><\/p>\n<ul>\n<li><strong>Okazaki fragments<\/strong> are short segments of DNA synthesized in the 5\u2019 to 3\u2019 direction (away from the unzip\/replication fork)\n<p><figure id=\"attachment_159\" aria-describedby=\"caption-attachment-159\" style=\"width: 300px\" class=\"wp-caption alignright\"><img loading=\"lazy\" decoding=\"async\" class=\"size-medium wp-image-159\" src=\"https:\/\/blogs.ubc.ca\/mrpletsch\/files\/2017\/02\/2.79-300x272.png\" alt=\"\" width=\"300\" height=\"272\" srcset=\"https:\/\/blogs.ubc.ca\/mrpletsch\/files\/2017\/02\/2.79-300x272.png 300w, https:\/\/blogs.ubc.ca\/mrpletsch\/files\/2017\/02\/2.79.png 486w\" sizes=\"auto, (max-width: 300px) 100vw, 300px\" \/><figcaption id=\"caption-attachment-159\" class=\"wp-caption-text\">Figure 9: Lagging strand replication<\/figcaption><\/figure><\/li>\n<li>Each subsequent piece is replicated <strong>more closely to the replication fork than the fragment before it.<\/strong><\/li>\n<li><strong>DNA Ligase (another enzyme)<\/strong> joins all the <strong>Okazaki fragments together <\/strong><\/li>\n<\/ul>\n<h3><strong><u>Protein synthesis and the Central Dogma<\/u><\/strong><\/h3>\n<p><strong>Central dogma<\/strong> \u2013 Explains the flow of genetic information within a biological system.<\/p>\n<ul>\n<li>\u201cDNA makes RNA and RNA makes protein\u201d<\/li>\n<li>Two processes: Transcription and Translation<\/li>\n<\/ul>\n<figure id=\"attachment_160\" aria-describedby=\"caption-attachment-160\" style=\"width: 429px\" class=\"wp-caption aligncenter\"><img loading=\"lazy\" decoding=\"async\" class=\" wp-image-160\" src=\"https:\/\/blogs.ubc.ca\/mrpletsch\/files\/2017\/02\/2.710-300x123.png\" alt=\"\" width=\"429\" height=\"183\" \/><figcaption id=\"caption-attachment-160\" class=\"wp-caption-text\">Figure 10: The Central Dogma<\/figcaption><\/figure>\n<h4><strong><u>Transcription<\/u><\/strong><\/h4>\n<p><em>Transcription is the process by which an RNA sequence is produced from a DNA template.<\/em><\/p>\n<ul>\n<li>Sections of DNA that code for a specific polypeptide are called genes.<\/li>\n<li>Gene = specific DNA sequence at specific location<\/li>\n<li>The DNA code is in the nucleus, but protein synthesis takes place outside nucleus on ribosomes.<\/li>\n<\/ul>\n<p><strong>Question: <\/strong><em>What needs to occur before protein synthesis can take place?<\/em><\/p>\n<ul>\n<li>There must be an intermediary molecule that carries DNA code outside of the nucleus.<\/li>\n<li>mRNA (Messenger RNA) is this molecule!<\/li>\n<\/ul>\n<p><strong>2.7.U4 &#8211; Transcription is the synthesis of mRNA copied from the DNA base sequences by RNA polymerase.<\/strong><\/p>\n<h5><strong>Steps of transcription:<\/strong><\/h5>\n<p><strong>RNA Polymerase \u2013 <\/strong>An enzyme that unzips a specific area of DNA (gene).<\/p>\n<ol>\n<li><strong>Iniation<\/strong><\/li>\n<\/ol>\n<ul>\n<li>RNA polymerase binds to specific sequence called<\/li>\n<li>RNA Polymerase begins to unzip an area of DNA.<\/li>\n<\/ul>\n<ol start=\"2\">\n<li><strong>Elongation<\/strong><\/li>\n<\/ol>\n<ul>\n<li>RNA nucleotides found in the nucleus are <u>added to the template strand<\/u> of the DNA by RNA polymerase (C-G, A-U) in the 5\u2019 to 3\u2019 direction. This is called <strong>elongation<\/strong>.<\/li>\n<li>RNA polymerase covalently bonds nucelotides of mRNA strand.<\/li>\n<\/ul>\n<p><strong><u>Things to consider (elongation):<\/u><\/strong><\/p>\n<ul>\n<li>RNA is single stranded, therefore only one strand of DNA is used as a template.<\/li>\n<li>DNA strand used as template = the <strong>template <\/strong>or <strong>antisense<\/strong> (3&#8242; to 5&#8242;) It is <strong>complementary to mRNA.<\/strong><\/li>\n<\/ul>\n<ul>\n<li>Unused DNA strand = the <strong>coding<\/strong> or <strong>sense strand<\/strong> (5&#8242; to 3&#8242;) and has the <u>same sequence as the mRNA.<\/u><\/li>\n<\/ul>\n<figure id=\"attachment_161\" aria-describedby=\"caption-attachment-161\" style=\"width: 300px\" class=\"wp-caption aligncenter\"><img loading=\"lazy\" decoding=\"async\" class=\"size-medium wp-image-161\" src=\"https:\/\/blogs.ubc.ca\/mrpletsch\/files\/2017\/02\/2.711-300x75.png\" alt=\"\" width=\"300\" height=\"75\" srcset=\"https:\/\/blogs.ubc.ca\/mrpletsch\/files\/2017\/02\/2.711-300x75.png 300w, https:\/\/blogs.ubc.ca\/mrpletsch\/files\/2017\/02\/2.711-768x192.png 768w, https:\/\/blogs.ubc.ca\/mrpletsch\/files\/2017\/02\/2.711-552x138.png 552w, https:\/\/blogs.ubc.ca\/mrpletsch\/files\/2017\/02\/2.711.png 975w\" sizes=\"auto, (max-width: 300px) 100vw, 300px\" \/><figcaption id=\"caption-attachment-161\" class=\"wp-caption-text\">Figure 11: The antisense strand acts as a template for mRNA synthesis<\/figcaption><\/figure>\n<ol start=\"3\">\n<li><strong>Termination<\/strong><\/li>\n<\/ol>\n<ul>\n<li>RNA polymerase reaches <strong>terminator (<\/strong>specific sequence that signals end of transcription) and mRNA strand detaches.<\/li>\n<\/ul>\n<ol start=\"4\">\n<li><strong>Processing<\/strong><\/li>\n<\/ol>\n<ul>\n<li>Eukaryotic genes are composed of protein-coding sequences called\u00a0<strong>exons\u00a0<\/strong>(<em>ex<\/em><em>ons are <\/em><em>ex<\/em><em>pressed<\/em>) and <strong>introns<\/strong> (<em>int<\/em>ervening)<\/li>\n<li>Intron sequences do not encode functional proteins.<\/li>\n<li>Therefore, introns must be removed by a complex molecular machine called a <strong>spliceosome <\/strong>\u2013 this process is called<\/li>\n<li>mRNA leaves the nucleus via the nuclear pore.<\/li>\n<\/ul>\n<p><strong>2.7.U7 &#8211; Codons of three bases on mRNA correspond to one amino acid in a polypeptide.<\/strong><\/p>\n<p>The genetic code is written in triplets (3 base code)<\/p>\n<p>DNA\u00a0 &#8212;&#8211;&gt; Transcription &#8212;&#8211;&gt; mRNA<\/p>\n<p><em>Triplet\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 Codon<\/em><\/p>\n<p>Each codon codes for one specific amino acid.<\/p>\n<p><strong>Question: <\/strong><em>If one codon (3 bases) code for 1 amino acid, what must the entire mRNA strand code for?<\/em><\/p>\n<p><em>\u00a0<\/em><\/p>\n<figure id=\"attachment_162\" aria-describedby=\"caption-attachment-162\" style=\"width: 407px\" class=\"wp-caption aligncenter\"><img loading=\"lazy\" decoding=\"async\" class=\" wp-image-162\" src=\"https:\/\/blogs.ubc.ca\/mrpletsch\/files\/2017\/02\/2.712-300x194.png\" alt=\"\" width=\"407\" height=\"268\" \/><figcaption id=\"caption-attachment-162\" class=\"wp-caption-text\">Figure 12: Codon translation table<\/figcaption><\/figure>\n<h4><strong><u>Translation<\/u><\/strong><\/h4>\n<p><em>Translation is the process of protein synthesis in which the genetic information encoded in mRNA is translated into a sequence of amino acids in a polypeptide chain.<\/em><\/p>\n<p><strong>2.7.U5<\/strong> &#8211;<strong>Translation is the synthesis of polypeptides on ribosomes.<\/strong><\/p>\n<p><strong>2.7.U6 &#8211; The amino acid sequence of polypeptides is determined by mRNA according to the genetic code.<\/strong><\/p>\n<p><u>Translation<\/u> takes place at the <u>ribosome<\/u>s (in cytoplasm or on the rough ER)<\/p>\n<p><u>Messenger RNA <\/u>(mRNA) carries information from a <u>specific gene to the ribosomes<\/u> in order to create the correct polypeptide.<\/p>\n<p><span style=\"text-decoration: underline;\"><strong>Types of RNA:<\/strong><\/span><\/p>\n<p><strong>mRNA (messenger RNA)<\/strong> single-stranded complementary copy of template DNA strand coding for a single polypeptide.<\/p>\n<p><strong>rRNA (ribosomal RNA)<\/strong> non-coding RNA which makes up ~60% of a ribosome composition. Helps decode mRNA into amino acids through interactions between mRNA and tRNA.<\/p>\n<p><strong>tRNA (transfer RNA)<\/strong> carries one of the 20 amino acids to the ribosome for polypeptide formation.<\/p>\n<figure id=\"attachment_163\" aria-describedby=\"caption-attachment-163\" style=\"width: 243px\" class=\"wp-caption alignright\"><img loading=\"lazy\" decoding=\"async\" class=\"size-medium wp-image-163\" src=\"https:\/\/blogs.ubc.ca\/mrpletsch\/files\/2017\/02\/2.713-243x300.png\" alt=\"\" width=\"243\" height=\"300\" srcset=\"https:\/\/blogs.ubc.ca\/mrpletsch\/files\/2017\/02\/2.713-243x300.png 243w, https:\/\/blogs.ubc.ca\/mrpletsch\/files\/2017\/02\/2.713.png 367w\" sizes=\"auto, (max-width: 243px) 100vw, 243px\" \/><figcaption id=\"caption-attachment-163\" class=\"wp-caption-text\">Figure 13: tRNA structure<\/figcaption><\/figure>\n<ul>\n<li>Contains a sequence called the anticodon, which can recognize and decode a specific complementary mRNA codon.<\/li>\n<li>Each tRNA has its corresponding amino acid attached to its end.<\/li>\n<li>When a tRNA recognizes and binds to its corresponding codon in the ribosome, the tRNA transfers the appropriate amino acid to the end of the growing polypeptide chain.<\/li>\n<li>Resembles a clover.<\/li>\n<\/ul>\n<p><span style=\"text-decoration: underline;\"><strong>Ribosome structure:<\/strong><\/span><\/p>\n<ul>\n<li>The <u>ribosomes<\/u> consist of a l<u>arge and a small subunit<\/u>.<\/li>\n<li>Each ribosomal subunit is made of rRNA and protein.<\/li>\n<li>The small subunit <strong>binds to mRNA.<\/strong><\/li>\n<li>The large subunit has <strong>binding sites for tRNA<\/strong>. Also, catalyzes peptide bonds between amino acids.<\/li>\n<\/ul>\n<figure id=\"attachment_164\" aria-describedby=\"caption-attachment-164\" style=\"width: 300px\" class=\"wp-caption aligncenter\"><img loading=\"lazy\" decoding=\"async\" class=\"size-medium wp-image-164\" src=\"https:\/\/blogs.ubc.ca\/mrpletsch\/files\/2017\/02\/2.714-300x198.png\" alt=\"\" width=\"300\" height=\"198\" srcset=\"https:\/\/blogs.ubc.ca\/mrpletsch\/files\/2017\/02\/2.714-300x198.png 300w, https:\/\/blogs.ubc.ca\/mrpletsch\/files\/2017\/02\/2.714-552x364.png 552w, https:\/\/blogs.ubc.ca\/mrpletsch\/files\/2017\/02\/2.714.png 675w\" sizes=\"auto, (max-width: 300px) 100vw, 300px\" \/><figcaption id=\"caption-attachment-164\" class=\"wp-caption-text\">Figure 14: Ribosomal subunits<\/figcaption><\/figure>\n<p><span style=\"text-decoration: underline;\"><strong>Steps of Translation:<\/strong><\/span><\/p>\n<p>1.<strong>Initiation<\/strong><\/p>\n<ul>\n<li>The small ribosomal subunit binds to the mRNA strand.<\/li>\n<li>The mRNA strand is \u201csandwiched\u201d between the small and large ribosome subunits.so that the first two codon triplets are within the boundaries of the ribosome.<\/li>\n<li>Complementary tRNA molecule joins with the first codon of the mRNA molecule (i.e. must have an <strong>anti-codon <\/strong>complementary to the mRNA <strong>codon<\/strong>) (<em>Which subunit contains tRNA binding sites?)<\/em><\/li>\n<li><strong>The first codon, or start codon, <\/strong>is AUG which codes for <strong>Methionine (Met). <\/strong>(Peptidyl (P) site on the large ribosomal subunit)<\/li>\n<\/ul>\n<p><strong>Question:<\/strong> <em>What would be the tRNA anti-codon for Methionine?<\/em><\/p>\n<figure id=\"attachment_165\" aria-describedby=\"caption-attachment-165\" style=\"width: 300px\" class=\"wp-caption aligncenter\"><img loading=\"lazy\" decoding=\"async\" class=\"size-medium wp-image-165\" src=\"https:\/\/blogs.ubc.ca\/mrpletsch\/files\/2017\/02\/2.715-300x216.png\" alt=\"\" width=\"300\" height=\"216\" srcset=\"https:\/\/blogs.ubc.ca\/mrpletsch\/files\/2017\/02\/2.715-300x216.png 300w, https:\/\/blogs.ubc.ca\/mrpletsch\/files\/2017\/02\/2.715-768x553.png 768w, https:\/\/blogs.ubc.ca\/mrpletsch\/files\/2017\/02\/2.715-552x397.png 552w, https:\/\/blogs.ubc.ca\/mrpletsch\/files\/2017\/02\/2.715.png 970w\" sizes=\"auto, (max-width: 300px) 100vw, 300px\" \/><figcaption id=\"caption-attachment-165\" class=\"wp-caption-text\">Figure 15: Ribosome &#8211; Translation initiation<\/figcaption><\/figure>\n<p><strong>2. Elongation<\/strong><\/p>\n<ul>\n<li>The next complementary tRNA anti-codon matches with the mRNA codon in the <strong>Aminoacyl (A) site<\/strong>.<\/li>\n<li>The two amino acids carried by the tRNA are side by side now.<\/li>\n<li>A condensation reaction occurs , covalently bonding the <strong>P site amino acid to the A site amino acid<\/strong>.<\/li>\n<li>The P site tRNA is released, the ribosome slides down the mRNA (A site tRNA is now at the P site), and a complementary tRNA anti-codon matches with the next mRNA codon at the <strong>now empty A site.<\/strong><\/li>\n<li>The ribosome only advancemence one codon at a time.<\/li>\n<li>To summarize &#8211; The ribosome travels down the mRNA, reading codons and bringing in the complementary tRNA\u2019s to translate the message out to protein.<\/li>\n<\/ul>\n<p><strong>3. Termination<\/strong><\/p>\n<ul>\n<li>Elongation continues until the ribosome reaches a STOP codon.<\/li>\n<li>The ribosome accepts a protein called a <strong>release factor<\/strong> instead of tRNA at the <strong>A Site.<\/strong><\/li>\n<li>The release factor breaks the bond between tRNA and the polypeptide \u2013 releasing both.<\/li>\n<\/ul>\n<p><iframe loading=\"lazy\" width=\"700\" height=\"525\" src=\"https:\/\/www.youtube.com\/embed\/5bLEDd-PSTQ?feature=oembed\" frameborder=\"0\" allowfullscreen><\/iframe><\/p>\n<h3>Central Dogma summary,<\/h3>\n<ul>\n<li><strong>DNA -&gt; RNA -&gt; PROTEIN<\/strong><\/li>\n<li>DNA is <strong>transcribed<\/strong> into single stranded mRNA molecules with the help of the enzyme <strong>RNA Polymerase.<\/strong><\/li>\n<li>The single stranded mRNA is <strong>complementary<\/strong> to the template (3\u2019 to 5\u2019) strand and <strong>identical <\/strong> to the <strong>coding (<\/strong>5\u2019 to 3\u2019) strand (Except replace T with U on mRNA)<\/li>\n<li>The synthesized mRNA molecule is able to leave to nucleus via the nuclear pore and heads to the ribosomes \u2013 the site of protein synthesis and translation.<\/li>\n<li>The two ribosomal subunits bind to the mRNA strand.<\/li>\n<li>tRNA carry specific <strong>anti-codons<\/strong> which are complementary to the mRNA codons. The tRNA binds mRNA codon, carrying a specific amino acid.<\/li>\n<li>The ribosome moves along the mRNA strand adding amino acids (translating the mRNA into a polypeptide).<\/li>\n<li>When a stop codon is reached, a release factor binds, releasing the polypeptide.<\/li>\n<li>Polypeptides are part, or the whole, of a specific protein which can have many functions around the body.<\/li>\n<\/ul>\n<p><strong>\u00a0<\/strong><\/p>\n<p><strong>\u00a0<\/strong><\/p>\n","protected":false},"excerpt":{"rendered":"<p class=\"post-excerpt\">Essential Idea: Genetic information in DNA can be accurately copied and can be translated to make the proteins needed by&#8230;<\/p>\n","protected":false},"author":48401,"featured_media":0,"comment_status":"closed","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"footnotes":""},"categories":[2064941],"tags":[],"class_list":["post-149","post","type-post","status-publish","format-standard","hentry","category-ib-biology"],"_links":{"self":[{"href":"https:\/\/blogs.ubc.ca\/mrpletsch\/wp-json\/wp\/v2\/posts\/149","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/blogs.ubc.ca\/mrpletsch\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/blogs.ubc.ca\/mrpletsch\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/blogs.ubc.ca\/mrpletsch\/wp-json\/wp\/v2\/users\/48401"}],"replies":[{"embeddable":true,"href":"https:\/\/blogs.ubc.ca\/mrpletsch\/wp-json\/wp\/v2\/comments?post=149"}],"version-history":[{"count":13,"href":"https:\/\/blogs.ubc.ca\/mrpletsch\/wp-json\/wp\/v2\/posts\/149\/revisions"}],"predecessor-version":[{"id":182,"href":"https:\/\/blogs.ubc.ca\/mrpletsch\/wp-json\/wp\/v2\/posts\/149\/revisions\/182"}],"wp:attachment":[{"href":"https:\/\/blogs.ubc.ca\/mrpletsch\/wp-json\/wp\/v2\/media?parent=149"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/blogs.ubc.ca\/mrpletsch\/wp-json\/wp\/v2\/categories?post=149"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/blogs.ubc.ca\/mrpletsch\/wp-json\/wp\/v2\/tags?post=149"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}