About problem 4 – can we really calculate this problem and find the inverse transform?

When I factor the denominator of , I found . I tried to use the basic formula of , but I think I could not use it since must be greater than 0, which in this case is 0.

Reason: if you have , eventually you are going to have to integrate it, either explicitly using the transform or inverse transform formula, or implicitly using a basic example.

When you eventually integrate it, the delta function is going to insist on , so the only value of that will ever matter is .

Question from a student:

Problem 4 is harder than I intended, but can still be solved.

Use partial fractions, then look at the terms as and . These are part of the transform of shifted heaviside functions.

Question from a student:

Yes.Reason: if you have , eventually you are going to have to integrate it, either explicitly using the transform or inverse transform formula, or implicitly using a basic example.

When you eventually integrate it, the delta function is going to insist on , so the only value of that will ever matter is .