Name: Rain Xia       Student Number: 59118159

There is a fountain in UBC campus which has a 5 meters radius and 1 meter height. If water flows into the fountain at a rate of 5 meters^3 per minute, how fast is the depth of the water increasing?

Given: dv/dt=5

Want: dh/dt

V=πr^2h

dv/dt=π*5^2*dh/dt

5=π*25*dh/dt

dh/dt=1/(5π)

Therefore the speed of the water increasing is 1/(5π) meter per minute.