# Koch Snowflake Example

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## Problem

Suppose we would like to calculate the area of the "Koch Snowflake". The Koch Snowflake is an object that can be created from the union of infinitely many equilateral triangles (see figure below). Starting with the equilateral triangle, this diagram gives the first three iterations of the Koch Snowflake (Creative Commons, Wikimedia Commons, 2007).

We construct the Koch Snowflake in an iterative process. Starting with an equilateral triangle, each iteration consists of altering each line segment as follows:

• divide the line segment into three segments of equal length
• draw an equilateral triangle that has the middle segment from step 1 as its base and points outward
• remove the line segment that is the base of the triangle from step 2

The Koch Snowflake is the limit approached as the number of iterations goes to infinity.

## Solution The Koch Snowflake after 5 iterations. The first iteration is blue, the second green, the third yellow, the fourth is red, and the fifth is black (Creative Commons, image from Wikimedia Commons).

Now, to derive an expression for the area of our construction at the iteration, let's start with the fifth iteration. The fifth iteration of the snowflake is shown below, with its iterations in different colours.

Blue and Green Triangles

Assume that the one blue triangle as unit area. Each side of the green triangle is exactly 1/3 the length of a side of the blue triangle, and therefore has exactly 1/9 the area of the blue triangle. There are three green triangles, so the green and blue triangles have an area of Blue, Green, and Yellow Triangles

Each of the 12 = 3•4 yellow triangles has 1/9 the area of a green triangle, or the area of a blue triangle. The area of the blue, green, and yellow triangles is Blue, Green, Yellow, and Red Triangles

Each of the 48 = 3•4•4 red triangles has 1/9 the area of a yellow triangles, or the area of a blue triangle. The area of the blue, green, yellow, and red triangles is Total Area

The total area of the snowflake uses the infinite sequence .

We will add all the terms of the series together, and add 1, to produce the following sum Seeing that this is a geometric series with a = 1/3 and r = 4/9, we immediately conclude that this series converges and is equal to Previous: A Geometric Series Problem with Shifting Indicies

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### 3 Responses to Koch Snowflake Example

1. Ryan Singley says:

This is all wrong. The number of yellow triangles is 12 not 9, and that makes the infinite sequence wrong as well.

2. yea says:

“each yellow triangle has 1/9 the area of a green triangle, or 1/27 the area of a blue triangle. ” But if a yellow triangle is 1/9 of a green triangle which is in turn 1/9 of a blue triangle, wouldn’t that make a yellow triangle equivalent to 1/81 of a blue triangle? Also- you say “The area of the blue, green, and yellow triangles is 1 + 3(1 / 9) + 9(1 / 27) = 5 / 3.”, you multiply 1/27 by 9 when it should be multiplied by 12 because there are 12 yellow triangles. Am I just really confused or is your math all wrong?

3. Geoffrey says:

This is wrong!
The r = 4/9 not 1/9.